5x-4=x^2+20

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Solution for 5x-4=x^2+20 equation: 



5x-4=x^2+20

We move all terms to the left:

5x-4-(x^2+20)=0

We get rid of parentheses

-x^2+5x-20-4=0

We add all the numbers together, and all the variables

-1x^2+5x-24=0

a = -1; b = 5; c = -24;
Δ = b2-4ac
Δ = 52-4·(-1)·(-24)
Δ = -71
Delta is less than zero, so there is no solution for the equation

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